I am new. Please solve this question. I am not from Russia or Kazakstan.
Two blocks of mass m have been placed on a bar of mass M. When released, find the acceleration of bar?
There is no friction anywhere.
Can someone help please?
может кто-нибудь помочь, пожалуйста
Welcome to the forum
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Sorry for the poor lighting, I can make up in latex if u want
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I do not think you are right. It is not given block 2 is at rest. How have you assumed that block 2 will be at rest when the block 1 is moving?
By the way, I wrote the absolute acceleration value. For the x-axis, it will be with a minus sign, that is, a large bar will move in the opposite direction.
There are few forces you missed
Rope affects the bar via the pulley, also block 2 and bar push each other as the accelerate, hence forces P and N
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Correct. I think this will be the way to solve. You are dealing with 4 variables so you will need 5 equations. First you will get from horizontal motion of block 2, second from the vertical motion of block 2, third from the motion of bar A, fourth from the horizontal motion of block 1, fifth and final from the relation between the accelerations of bar A and blocks 1&2.
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Right, sorry for my mistake.
T=ma_{2} \\
ma_{2}=mg-T \\
a_{2}=\frac{g}{2} \\
Mv_{1}=mv_{2} \\
Ma_{1}=ma_{2} \\
a_{1}=\frac{m}{M} \cdot \frac{g}{2}
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